In the energy-balanced Pearson's Square with grain mix A (40% corn and 60% SBH) at 1.62 Mcal/kg and grain mix B (50% DDG and 50% CSH) at 1.22 Mcal/kg, what is the total parts after subtracting across the diagonal?

In the energy-balanced Pearson's Square with grain mix A (40% corn and 60% SBH) at 1.62 Mcal/kg and grain mix B (50% DDG and 50% CSH) at 1.22 Mcal/kg, what is the total parts after subtracting across the diagonal?

• A. 0.40
• B. 0.22
• C. 0.18
• D. 1.00

Answer: (A)

In a Pearson's Square, when balancing two ingredients to a target energy that lies between their energies, the two diagonal differences add up to the difference between the two ingredient energies. So the total parts equal E1 minus E2. Here, E1 = 1.62 Mcal/kg and E2 = 1.22 Mcal/kg. The total parts = 1.62 − 1.22 = 0.40. This is why 0.40 is the correct total. The two individual parts would be Eth − 1.22 and 1.62 − Eth, which sum to 0.40.

In a Pearson's Square, when balancing two ingredients to a target energy that lies between their energies, the two diagonal differences add up to the difference between the two ingredient energies. So the total parts equal E1 minus E2.

Here, E1 = 1.62 Mcal/kg and E2 = 1.22 Mcal/kg. The total parts = 1.62 − 1.22 = 0.40. This is why 0.40 is the correct total. The two individual parts would be Eth − 1.22 and 1.62 − Eth, which sum to 0.40.